I tried again tonight. For some reason, I got results that seem to make sense. I don't know what I did differently. I tackled it two ways, using the dial indicator as before, and looking for a 90 degree relation of the valve stem and roller centerline to shaft centerline at half lift. Does this look more like you would expect, Ted and is my logic about half lift sound?
Tonight's results:
Shim, lift
.197", .453"
.250", .458"
.297", .454
Re the 90 degrees at half lift:
I started by measuring the lift with no shims, and then set it at half lift. I found that a 3/16" allen wrench lined up almost perfectly with the od of the roller axle when set on the spring retainer, so I laid that across the retainer and measured from the od of the rocker shaft to the allen wrench. I measured several times since it's tricky to do while leaning under a hood, to make sure it was accurate. I got about .260". I measured the shaft at about .775" and the roller axle at about .275"
So from center of the roller to the allen wrench is about .138"
That means the rocker shaft centerline needs to be .138" higher than the allen wrench. Center of the shaft is about .388" + .138" = .526" to the od of the shaft at the correct shim height. .526" - .260" = .266" of shim required. I can't do .266" of shim so I started at .250". Since I know it needs to be .526" higher than the allen wrench, I made a gauge out of an index card that I could use to compare against the distance between the wrench and od of the shaft. At .250" it is about perfect. At .197" it is a bit low and at .297" it is a bit high.
To find half lift, using the .250" shims, I start with the valve closed, with the indicator at .600".
Full lift was .142", so lift = .600" - .142" = .458"
.458" / 2 = .229"
So I set the indicator at .229" + .142" = .371" for half lift, to check for the 90 degree relation.
If this is all good, then I will also need taller valve covers in order to use the 1/4" shims
Lawrenceville, GA